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X^2+5X+3X=180
We move all terms to the left:
X^2+5X+3X-(180)=0
We add all the numbers together, and all the variables
X^2+8X-180=0
a = 1; b = 8; c = -180;
Δ = b2-4ac
Δ = 82-4·1·(-180)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-28}{2*1}=\frac{-36}{2} =-18 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+28}{2*1}=\frac{20}{2} =10 $
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